2[2x-(3x-4)]=3(x-4)

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Solution for 2[2x-(3x-4)]=3(x-4) equation:


Simplifying
2[2x + -1(3x + -4)] = 3(x + -4)

Reorder the terms:
2[2x + -1(-4 + 3x)] = 3(x + -4)
2[2x + (-4 * -1 + 3x * -1)] = 3(x + -4)
2[2x + (4 + -3x)] = 3(x + -4)

Reorder the terms:
2[4 + 2x + -3x] = 3(x + -4)

Combine like terms: 2x + -3x = -1x
2[4 + -1x] = 3(x + -4)
[4 * 2 + -1x * 2] = 3(x + -4)
[8 + -2x] = 3(x + -4)

Reorder the terms:
8 + -2x = 3(-4 + x)
8 + -2x = (-4 * 3 + x * 3)
8 + -2x = (-12 + 3x)

Solving
8 + -2x = -12 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
8 + -2x + -3x = -12 + 3x + -3x

Combine like terms: -2x + -3x = -5x
8 + -5x = -12 + 3x + -3x

Combine like terms: 3x + -3x = 0
8 + -5x = -12 + 0
8 + -5x = -12

Add '-8' to each side of the equation.
8 + -8 + -5x = -12 + -8

Combine like terms: 8 + -8 = 0
0 + -5x = -12 + -8
-5x = -12 + -8

Combine like terms: -12 + -8 = -20
-5x = -20

Divide each side by '-5'.
x = 4

Simplifying
x = 4

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